Correct answer: Qc81...e1Q[a]/e1B[a] 2.Qg2#[A] 1...e1N/[б]/ 2.Qf2#[Б] 1...N:h3[c] 2.Q:e2#[C] 1...Ng4/Ng8/Nh5/Nh7/Ne4[d]/Ne8/Nd5[e]/Nd7[f] 2
