Correct answer: Qf21...Be5/Bg3[a]/Bh2[a]/Bc7[a]/Bb8[a] 2.Ndb4#[A] 1...Be7/[б]//Bf8/[б]//Bc5/[б]//Ba3/[б]/ 2.Nf4#[Б] 1...Ng3[c]/Nh2[c]/Ne3[d]/N