Correct answer: Nb61...Nf1[a]/Nf3[a]/Nc4[a]/Nb1[a]/Nb3[a] 2.Nf3#[A] 1...Nc2/[б]//Nc6/[б]//Nd3/[б]//Nd5/[б]//Na2/[б]//Na6/[б]/ 2.Nc6#[Б] 1...e:d6[c] 2.Q<