Correct answer: Q:c51...f:g3[a] 2.Qg4#[A] 1...Rd1/[б]//Rd4[d]/Rd5/[б]//Re2[f] 2.Qe2#[Б] 1...Rd3[c]/Rc2[e]/Rb2[e]/Ra2[e]/Rf2[c] 2.Q:d3#[C] 1...Nh3[g]/N