Correct answer: Qf81...Nb3[a]/Nb7[a]/Nc4[a]/Nc6/[б]/ 2.Nbc6#[A] 1...Bc5[c]/B:c7[e] 2.R:e6#[Б] 1...B:d4[d] 2.Q:g5#[C] 1...e3[f] 2.N:d3#[D] 1.c8R? zz 1.
