Correct answer: Qb71...Nf6[a] 2.e:f6#[A] 1...Nc2/[б]//Nc6[c]/Nd3/[б]//Na2/[б]/ 2.Qc4#[Б] 1...Nd5[d] 2.Qf5#[C] 1...e:d6[e] 2.e:d6#[D] 1.Kc7? zz 1...Nf6[a] 2.e:f6#[A]
