Correct answer: N:c41...Nd4[a]/Nd8/[б]//Nb4[d]/Nb8[e]/Na7/[б]/ 2.Q:c4#[A] 1...N:e5+[c] 2.Q:e5#[Б] 1...N:a5[f] 2.Q:a5#[C] 1.Qb8? (2.Ra3#[D]/Qb2#)
