Correct answer: Qd71...Kc4[a]/Ne6[d] 2.Q:e4#[A] 1...Nh5/[б]//Nf5[c]/Ne8/[б]/ 2.Qg8#[Б] 1...Nf2[e]/Nf6[f]/Ng3[e]/Ng5[e]/Nc5[e] 2.Qc4#[C] 1...a3 2.B
