Correct answer: Qc31...f3[a]/Nf3/[б]/ 2.Qf5#[A] 1...Nf7[c]/Ng4[d]/Ng6[c]/Nd7[c]/Nc4[f]/Nc6[c] 2.d3#[Б] 1...Nd3[e] 2.f3#[C] 1...Nf6/Ng7/Nd6/Nc7 2.N
