Correct answer: Nb31...N:f3/Nf7[a]/Ng4[a]/Ng6[a]/Nd3/[б]//Nd7[c]/Nc4[d] 2.Qc6#[A]/Qc4#[Б] 1...Nc6[e] 2.Q:c6#[A] 1...Nf2[f]/Ng3[f]/Ng5[f]/Nd2[
