Correct answer: Qa51...Nd5[a]/d5[f] 2.Qd7#[A] 1...Ne6/[б]//Ne8[c]/Nb5[d]/Na6[e]/Na8[c] 2.Na5#[Б] 1...Be7 2.N:e7# 1.Ba6? zz 1...Nd5[a]/N:a6[e] 2.<
