Correct answer: R:f41...Nd3[a]/Nd7/[б]//Ne6[d]/Nb3/[б]//Na6/[б]/ 2.Bd6#[A] 1...Ne4[c] 2.Rd5#[Б] 1...e:f2[e]/e2[f] 2.Q:f4#[C] 1.Kd8? zz 1...Nd3[a]/Nd7/[б