Correct answer: Q:f41...K:b1[a]/Nd3[d]/Ne2[d] 2.Qd3#[A] 1...B:b1/[б]//R:b1/[б]/ 2.Rd2#[Б] 1...Bc3[c]/Bd4[c]/Be5[c]/Bf6[c]/Bg7[c]/Bh8[c] 2.Rd:c1#[C]
