Correct answer: Qe21...Bd2[a]/Rd3[a]/Re1[a]/Rf1[e]/Rg1[a]/Rh1[f] 2.Rd3#[A] 1...Bb2/[б]//Ba3[c]/Rd2/[б]/ 2.B:e3#[Б] 1...d:e4[d] 2.Qd7#[C] 1.Qg2? zz