Correct answer: Qf11...Kd5[a]/f:e3 2.Qf5#[A] 1...d5/[б]/ 2.Bd3#[Б] 1...f3[c] 2.Qe6#[C] 1.Kg5? zz 1...Kd5[a] 2.Qf5#[A] 1...d5/[б]/ 2.Bd3#[Б] 1...f3[c] 2.Qe6#[C]
