Correct answer: Rd51...B:d7[a] 2.Qc4#[A] 1...Bg5/[б]//Be3[c]/Bd2[c]/Bc1[d] 2.Qg4#[C] 1...e4[e] 2.Ned4#[D] 1...Nf6/Ng7/Nd6/Nc7 2.Rd6#[Б] 1.Nfg
