Correct answer: Nc41...Nb3[a]/Nc2/[б]/ 2.Bc2#[A] 1...Rb3[c]/Rb2/Rb1[d]/Rb6[e]/Rb7[e]/Rb8[e] 2.Nc5#[C] 1...Ra5[f]/Rd5[f]/Re5/Rf5[g]/Rg5[f]/