Correct answer: Qf41...c3[a] 2.Qd5#[A] 1...d6/[б]/ 2.Qa5#[Б] 1...d5[c] 2.Qb4#[C] 1...Ng3/Nh4/Nh6/Ne3/Ne7/Nd4/Nd6 2.Qd4# 1.Ke8[D]? zz 1...c3[a] 2.Q<