Correct answer: Qa81...c:b5[a] 2.c6#[A] 1...e4/[б]/ 2.Qg7#[Б] 1...d:c4[c] 2.Qd7#[C] 1...c2 2.Qa1# 1.Qb7? zz 1...c:b5[a] 2.Q:d5#[D] 1...e4/[б]/ 2.Qg7#[Б] 1...d:c4[c] 2.Qd7#[C]
