Correct answer: Qc21...N:d4[a] 2.Nc3#[A] 1...Nc4/[б]/ 2.Q:b7#[Б] 1...Nc6[c] 2.Q:f7#[C] 1...Nc1/Nc5/Nd2/Na1 2.Qc5# 1.K:f7? zz 1...N:d4[a] 2.N