Correct answer: Qf31...e:d4[a] 2.Qg6#[A] 1...e4/[б]/ 2.Qf1#[Б] 1...c2[c] 2.R:d2#[C] 1.Qh1? zz 1...e:d4[a] 2.Qh7#[G] 1...e4/[б]/ 2.Qf1#[Б] but 1...c2[c]! 1.Qc6? zz 1...e4/