Correct answer: Qc51...Nf6[a]/Ng7/[б]//Nd6[c]/Nc7/[б]/ 2.N:f6#[A] 1...e5[d] 2.Qf5#[Б] 1...Nf4[e]/Ng1[e]/Ng3[e]/Nd4[e]/Nc1[e]/Nc3[e] 2.Q:f4#[C] 1.K<