Correct answer: Qg11...Kf3[a] 2.Bd5#[A] 1...e2/[б]/ 2.Q:e2#[Б] 1...f3[c] 2.Qh4#[C] 1.Kh2? zz 1...e2/[б]/ 2.Q:e2#[Б] 1...f3[c] 2.Qh4#[C] but 1...Kf3[a]! 1.Kh4? zz