Correct answer: Bd41...Ne5[a]/Nf6/[б]//Nf8/[б]//Nc5/[б]//Nb6/[б]//Nb8/[б]/ 2.N:e5#[A] 1...Ng3[c]/Nh2[c]/Ne3[c]/Nd2[d] 2.Nd2#[Б] 1...d2[e] 2.Qe4#[C] 1.
