Correct answer: Qd71...Nb6[a]/Nc7/[б]/ 2.Q:b6#[A] 1...d4[c] 2.Qe5#[Б] 1...Bb5[d]/Bc4/Bd3/Be2/Bf1 2.N:b7#[C] 1...a3 2.Nb3# 1...Nh6/Nf6/Ne7 2.Q