Correct answer: Qa31...Kf4[a]/Kd4[c] 2.Qe4#[A] 1...K:f6/[б]/ 2.Qh8#[Б] 1...K:d6[d] 2.Qb8#[C] 1.d7? zz 1...Kf4[a]/Kd4[c] 2.Qe4#[A] 1...Kd6[d] 2.Qb8#
