Correct answer: e:f41...Ng3[a]/Ng7[a]/Nf6/[б]/ 2.R:f4#[A] 1...Nc1[c]/Nc5[c]/Nd2[c]/Nd4[d]/Na1[c]/Na5[c] 2.Rd4#[Б] 1...c5 2.B:d5# 1...d4 2.Q:c6# 1...f:e
