Correct answer: Qb21...Ke5[a]/e2[c] 2.Qe7#[A] 1...Kd3/[б]//f3 2.Nc5#[Б] 1.Bg1? zz 1...Ke5[a] 2.Qe7#[A] 1...Kd3/[б]/ 2.Nc5#[Б] 1...e2[c] 2.Q:d4#/Qe7#[A]
