Correct answer: Na41...d:c3[a] 2.Qd7#[A] 1...Ne4/[б]//Nf3[c]/Nc4[d]/Nb1/[б]//Nb3[e] 2.Qc4#[Б] 1...N:g3/Nh2/Ne3 2.R:d2# 1.Kh4? zz 1...d:c3[a] 2.Qd
