Correct answer: Qh61...Bg5[a]/Bh4[a]/Bg7[a]/Bh8[a]/Be7/[б]//Bd8[a] 2.f6#[A] 1...e2[c] 2.Qd3#[Б] 1...Nb3/Nb7/Nc4/Nc6+ 2.Bc6# 1.Qf3?? (2.Qd1#)
