Correct answer: e:d51...Nh4[a]/Nh8/[б]//Nf8 2.Q:f4#[A] 1...N:f5[c]/Ng8/Nc6/Nc8[d] 2.R:d5#[Б] 1.Rh4? zz 1...Nh8/[б]//Nf8 2.Q:f4#[A] 1...N