Correct answer: Nd71...Nb6[a] 2.K:b6#[A] 1...Nc7/[б]/ 2.K:c7#[Б] 1...Nf2[c]/Ng3[c]/Ng5[c]/Nd2[c]/Nc5[c] 2.Kc5#[C] 1...N:d6[d] 2.K:d6#[D] 1...f4 2.Q:e4#
