Correct answer: Qa41...Bc3[a] 2.b:c3#[A] 1...B:d2/[б]/ 2.b3#[Б] 1...Ba3[c] 2.b:a3#[C] 1...Ba5[d] 2.b4#[D] 1...d:c4[e] 2.Nb3#[E] 1...Ng2/Nh3/Nh5/Ne2/Ne6/Nd3 2.R<