Correct answer: Qd81...R:c3+[a] 2.Q:c3#[A] 1...R:c5/[б]/ 2.Q:c5#[Б] 1...Rb4[c] 2.Q:b4#[C] 1.c6? zz 1...R:c3+[a] 2.Q:c3#[A] 1...Rc5/[б]/ 2.Q:c5#[Б] 1...R<