Correct answer: Qc71...Kf3[a] 2.Qd5#[A] 1...K:f5/[б]/ 2.Qd3#[Б] 1.Qe5+? 1...Kf3[a] 2.Qd5#[A] 1...Kd3[c] 2.Qe3#[E] but 1...f:e5! 1.N:f7?? zz 1...K