Correct answer: Ng31...N:e4[a] 2.Be5#[A] 1...Ne6/[б]//Nb3[c]/Nb7[c]/N:a4[c]/Na6[c] 2.Qd5#[Б] 1...K:e4 2.Qc4# 1.Re6? (2.Bg1#[C]) 1...N:e4[a] 2.