Correct answer: B:d51...Kf4[a] 2.Qf6#[A] 1...Nc2/[б]//Nc6/[б]//Na2/[б]//Na6/[б]//d4 2.Bg3#[Б] 1.R:b4?? (2.Bg3#[Б]) but 1...a:b4! 1.B:g2?? zz 1...Kf4[a]/d4