Correct answer: Nd21...Ke2[a] 2.Qc4#[A] 1...Kc2/[б]/ 2.Qe4#[Б] 1.K:a5?? zz 1...Ke2[a] 2.Qc4#[A] but 1...Kc2/[б]/! 1.Kb3?? (2.Qc4#[A]) but 1...a4+! 1.K<