Correct answer: f61...Nc4[a]/Nc8/[б]//Na4[a]/Na8[c] 2.N:d7#[A] 1...d6[d] 2.Qe6#[Б] 1.Kc7? zz 1...Nc4[a]/Nc8/[б]//Na4[a] 2.N:d7#[A] 1...d6[d] 2.Qe6#[Б
