Correct answer: Qh31...Bh4[a]/Bf2/[б]//Be1[c] 2.Q:f4#[A] 1...Bc2[d]/Bd1[e]/Bc4[f]/Ba2[f] 2.Re3#[Б] 1.Rd1? zz 1...Bh4[a]/Bf2/[б]//Be1[c] 2.Q:
