Correct answer: Bf41...Nc3[a]/Nc7/[б]//Nd4[c]/Nd6[d]/Na3[e]/Na7/[б]/ 2.Rd4#[A] 1...Ng3[f]/Nh2[g]/Ne3[h]/Nd2[g] 2.Re3#[Б] 1...Bh2 2.N:f2# 1...R<