Correct answer: c51...d2[a] 2.Qh3#[A] 1...d5/[б]/ 2.c:d5#[Б] 1...e4 2.Qh8# 1...b5 2.c:b5# 1.Qf8? zz 1...d2[a] 2.Qf3#[C] 1...d5/[б]/ 2.Qb4#[D] 1...e4 2.Qf6#/Qh8#/Qg7#
