Correct answer: Qa11...B:b3[a] 2.Q:b3#[A] 1...c2/[б]/ 2.Q:d2#[Б] 1...Qg2+ 2.B:g2# 1...Q:h1+ 2.Q:h1# 1...Qe4 2.B:e4# 1.Kg1? zz 1...B:b3[a] 2.Q:b3#[A]