Correct answer: Be21...c3[a] 2.B:d3#[A] 1...Nf4/[б]//Nef8[c]/Ng5[d]/Ng7[c]/Nd4/[б]//Nd8[e]/Nec5[e]/Nc7[f] 2.R:f4#[C] 1...g3[g] 2.Q:f3#[D] 1...f2[h] 2.Bg2#[E]