Correct answer: Qc71...Rh6[a]/Rh5[a]/Rh4/[б]//Rh3[c]/Rh2[d]/Rh1[a]/Rh8[a] 2.B:g7#[A] 1...c5[e] 2.Q:d5#[Б] 1...a4 2.R:b4# 1...c2 2.e3# 1.Kf3? zz 1...Rh
