Correct answer: Bd61...Nd7[a]/Na6[a] 2.Ba6#[A] 1...Nd4/[б]//Nd8[c]/Ne5[d]/Ne7/[б]//Nb4[e]/Na5[d]/Na7/[б]/ 2.Qa5#[Б] 1.Bd8? zz 1...Nd7[a]/Na6
