Correct answer: Nc21...Be2[a]/Bd1[a]/B:e4[a] 2.Na2#[A] 1...e:d4/[б]/ 2.Qe1#[Б] 1.Nc6? zz 1...Be2[a]/Bd1[a]/B:e4[a] 2.Qe1#[Б] 1...e:d4/[б]/ 2.Q:d4#[C] but
