Correct answer: Bc31...Ne3[a]/Ne7[a]/Nf4[a]/Nf6/[б]//Ndc3/Ndc7[c]/Nb4[d]/N:b6[a] 2.Nd:e3#[A] 1...Nbc3/Nbc7[e]/Na3[e]/Na7[e] 2.Nb2#[Б] 1...N:d
