Correct answer: Qb11...c:b4[a]/c4/[б]/ 2.Qd4#[A] 1...Nc4[c]/Nd1[d]/Nd3[e]/Na4[d] 2.N:c4#[Б] 1.Qd5? zz 1...c:b4[a] 2.Qd4#[A] 1...c4/[б]/ 2.Qd4#[A]/Q:b5#/R:b5
