Correct answer: Kc41...Ng4[a]/Ng8[a]/Nh5[a]/Nh7[a]/Ne4[a]/Ne8[a]/Nd5[a]/Nd7[a] 2.Ke4#[A] 1...Nb3/[б]//Nc2/[б]/ 2.Kc2#[Б] 1...Bc1/Bc3/Ba3 2.
